[Campbell Biology P.1187] Based on the hopping experiment data provided, what is the approxim... | Practice Question
Based on the hopping experiment data provided, what is the approximate energy cost per hop at the lower frequency 0.92 hops/sec compared to the higher frequency 1.85 hops/sec , after accounting for standing energy 159 joules/sec , and what does this difference suggest about energy storage in tendons?
Explanation
First, calculate the net energy used per second by subtracting the standing energy 159 J/sec from the total energy used: - For 1.85 hops/sec: 735 J/sec - 159 J/sec = 576 J/sec - For 0.92 hops/sec: 716 J/sec - 159 J/sec = 557 J/sec Next, calculate the energy cost per hop by dividing the net energy by the frequency: - For 1.85 hops/sec: 576 J/sec / 1.85 hops/sec ≈ 311.35 J/hop - For 0.92 hops/sec: 557 J/sec / 0.92 hops/sec ≈ 605.43 J/hop This shows that the energy cost per hop is significantly higher at the lower hopping frequency. This difference suggests that at higher frequencies, the tendons are more effectively utilized to store and release elastic energy, much like a spring. This elastic recoil reduces the metabolic energy cost per hop, making higher frequency hopping more energetically efficient per unit of movement. At lower frequencies, less elastic energy is recovered, requiring more active muscle work per hop.